Matematika Sekolah Menengah Atas f(x) = ax + b

f(3) = 6
f(1) = 4

tentukan nilai 3a + 2b = ...​

f(x) = ax + b

f(3) = 6
f(1) = 4

tentukan nilai 3a + 2b = ...​

Jawaban:

9

Penjelasan dengan langkah-langkah:

f(3)= 6

3a+b= 6

f(1)= 4

a+b= 4

3a+b= 6

a+b= 4

------------ -

2a= 2

a= 1

a+b= 4

1+b= 4

b= 3

3a+2b

3(1)+2(3)

= 3+6

= 9

f(x) = ax + b

...

f(3) = a(3) + b

6 = 3a + b

3a + b = 6 ...... pers 1

f(1) = a(1) + b

4 = a + b

a + b = 4 ...... pers 2

.

Eliminasi pers 1 dan 2

3a + b = 6

a + b = 4

----------------- -

2a = 2

a = 2/2

a = 1

..

Substitusi a ke pers 2

a + b = 4

1 + b = 4

b = 4 - 1

b = 3

~~~

Maka,

3a + 2b

= 3(1) + 2(3)

= 3 + 6

= 9

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